KX Developer Visual Inspector Multiple X points

Community Support
,
1

https://learninghub.kx.com/forums/topic/kx-developer-visual-inspector-multiple-x-points

Hello,

I cant seem to figure out if this is possible but i want to compare 2 different price columns at a time over certain period. Is this possible on the visual inspector?

My table looks like this:

time       price pricev2 
------------------------------ 
00:00:00.002 6.33 6.32 
00:00:01.001 4.05 4.05 
00:00:26.808 4.05 5.07 
00:00:27.002 5.12 5.12 
00:00:28.002 2.61 2.61 
00:00:29.002 4.61 4.47 
00:00:30.001 4.9 4.47 
00:00:31.000 4.64 4.77 
00:00:32.000 2.37 4.87 
00:00:33.000 3.75 2.7

 

I want a line for each price to show how off the prices are at a certain time

2

One option would be to unpivot the table using a helper function

 

/tab : the table to operate on 
/baseCols : the columns not to unpivot 
/pivotCols : the columns which you wish to unpivot 
/kCol : the key name for unpivoted data 
/vCol : the value name for unpivoted data 
unpivot:{[tab;baseCols;pivotCols;kCol;vCol] 
    base:?[tab;();0b;{x!x}(),baseCols]; 
    newCols:{[k;v;t;p] flip (k;v)!(count[t]#p;t p)}[kCol;vCol;tab] each pivotCols; 
    baseCols xasc raze {[b;n] b,'n}[base] each newCols } 

unpivot[;`time;`price`pricev2;`priceType;`price] table 
time       priceType price 
---------------------------- 
00:00:00.002 price   6.33 
00:00:00.002 pricev2 6.32 
00:00:01.001 price   4.05 
00:00:01.001 pricev2 4.05 
00:00:26.808 price   4.05 
00:00:26.808 pricev2 5.07 
00:00:27.002 price   5.12 
00:00:27.002 pricev2 5.12 
00:00:28.002 price   2.61 
00:00:28.002 pricev2 2.61 
00:00:29.002 price   4.61 
00:00:29.002 pricev2 4.47 
00:00:30.001 price   4.9 
00:00:30.001 pricev2 4.47 
00:00:31.000 price   4.64 
00:00:31.000 pricev2 4.77 
00:00:32.000 price   2.37 
00:00:32.000 pricev2 4.87 
00:00:33.000 price   3.75 
00:00:33.000 pricev2 2.7

 

 

 

Then you can set the options to graph the lines

 

 

3

In the visual inspector you can enter qsql queries.

 

Here are some example which may help. Firstly I recreated your table:

 

table:flip `time`price`pricev2!( (00:00:00.002 00:00:01.001 00:00:26.808 00:00:27.002 00:00:28.002 00:00:29.002 00:00:30.001 00:00:31 00:00:32 00:00:33); (6.33 4.05 4.05 5.12 2.61 4.61 4.9 4.64 2.37 3.75); (6.32 4.05 5.07 5.12 2.61 4.47 4.47 4.77 4.87 2.7));

 

Uses flip to create a table from a dictionary.

 

You can compare the columns using subtract:

 

update priceDiff:price-pricev2 from table 
time        price pricev2 priceDiff 
------------------------------------ 
00:00:00.002 6.33 6.32    0.01 
00:00:01.001 4.05 4.05    0 
00:00:26.808 4.05 5.07    -1.02 
00:00:27.002 5.12 5.12    0 
00:00:28.002 2.61 2.61    0 
00:00:29.002 4.61 4.47    0.14 
00:00:30.001 4.9  4.47    0.43 
00:00:31.000 4.64 4.77    -0.13 
00:00:32.000 2.37 4.87    -2.5 
00:00:33.000 3.75 2.7     1.05

 

 

You can use within to query within a time window:

 

select from table where time within 00:00:01 00:00:30 
time       price pricev2 
-------------------------- 
00:00:01.001 4.05 4.05 
00:00:26.808 4.05 5.07 
00:00:27.002 5.12 5.12 
00:00:28.002 2.61 2.61 
00:00:29.002 4.61 4.47

 

 

Then you can combine the 2 statements in to one:

 

update priceDiff:price-pricev2 from select from table where time within 00:00:01 00:00:30 
time      price pricev2 priceDiff 
------------------------------------ 
00:00:01.001 4.05 4.05  0 
00:00:26.808 4.05 5.07  -1.02 
00:00:27.002 5.12 5.12  0 
00:00:28.002 2.61 2.61  0 
00:00:29.002 4.61 4.47  0.14

 

 

This page has lots more examples: qsql

Hopefully this helps you.

4

Hey rocuinneagain,

Thank you for this but unfortunately this isnt what i was looking for. I want to use KX Developer visual inspector to view a line graph with both price and pricev2 as separate lines against time.

5

Thanks so much, this is exactly what i was looking for