like comparison

Academy Support
1

https://learninghub.kx.com/forums/topic/like-comparison

Hi:

 

not sure why for the below two like comparison, the first one returns 1 and second type error? given both are comparing a symbol on the left to its equivalent in string.

 

`IBM like "IBM" 
`t like "t"

 

thanks,

2

it does not get shown properly but IBM and t should be symbol type,

3

like takes a string on the right. "IBM" is a string. "t" is not a string but a character - this is a quirk in the syntax. If you want to have a one-character string you have to use enlist, in this case enlist"t".

4 
q)type"t" // t is a character atom - 'like' expects a character vector 
-10h 
q)type"IBM" // IBM is a character vector 
10h 
q)type enlist "t" // You can enlist an atom to be a single item vector 
10h 
q)type (),"t" // (), is useful as a conditional enlist. It enlists the atom 
10h 
q)type (),"IBM" // It does not enlist the vector 
10h
5

Thank you both!