Namespaces Quiz

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1

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Hi all, would anybody be able to help me here. I want to create ( .animal.dog) and ( .animal.cat) using sv however I end up just joining cat and dog to animal to get this. 

 

I have created the namespace when n and v are single symbols however I’m running into errors when they are lists of symbols. 

 

Any help is greatly appreciated.

2

Lots of ways to do this, my first thought was to append  the cat dogs to the `animal making two lists and then separately performing the sv

q).animal ,/: catdog .animal cat .animal dog q) sv ’ .animal ,/: catdog .animal.cat`.animal.dog

If you don’t have the . before animal you could write like this

q)sv’[`]``animal,/:`cat`dog `.animal.cat`.animal.dog

There might be a more elegant implementation here, but should help…

3

Thank you very much for your help!

4

Just on that note, I realise this was not your question but as it pertains to namespaces wanted to provide some flavour around namespace definition alternate methods

// Definining namespace q).test:((::),a,b)!((::),1,2) q).test ::| :: a| 1 b| 2 // However we can create the namespace as an empty // dictionary and assign keys after creation q).test:{x!x}enlist(::) q).test[a]:1 q).test[b]:2 q).test ::| :: a| 1 b| 2 // also acceptable method q).test:{x!x}enlist(::) q).test[ab]:1 2 q).test ::| :: a| 1 b| 2

 

5

Slight correction on Paul’s second answer. Creating a template namespace should have backtick ` as key not (::)

q).test.a:1
q).Q.s1 .test
"``a!(::;1)"

So you create a template like:

q).test:enlist[`]!enlist(::)
q).Q.s1 .test
"(,`)!,::"
q).test[`a]:1
q).Q.s1 .test
"``a!(::;1)"

 

q)ns:`animal
q)n:`dog`cat
q)v:`rover`whiskers
q)sv[`;`,ns] set enlist[`]!enlist (::) //Create the empty namespace
`.animal
q).Q.s1 .animal
"(,`)!,::"
q)@[` sv `,ns;n;:;v] //Add the values
`.animal
q).animal
| ::
dog| `rover
cat| `whiskers