# Re: \[personal kdb+\] Simple Query

**URL:** <https://forum.kx.com/t/re-personal-kdb-simple-query/12102>\
**Category:** Community Support\
**Tags:** kdb-and-q\
**Created:** [December 24, 2020, 6:38pm UTC](https://forum.kx.com/t/re-personal-kdb-simple-query/12102 "2020-12-24T18:38:00Z")\
**Posts on this page:** 1\
**Page:** 1

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**Author:** ![Nick10](https://avatars.discourse-cdn.com/v4/letter/n/e68b1a/32.png) [@Nick10](https://forum.kx.com/u/Nick10)\
**Post date:** [December 24, 2020, 6:38pm UTC](https://forum.kx.com/t/re-personal-kdb-simple-query/12102/1 "2020-12-24T18:38:00Z")

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hello gene,

you have two choices:

- use the ‘like’ operator

update status:not name like “” from t

- use the length of each string:

update status:0\<count each name from t