James11
1
q) table1:(a:(1 1 3 1);b:(4 5 4 4);d:(7 8 9 6))
q) table2:(a:(1 2 3);b:(4 5 6);c:(7 8 9))
q) show aj[a
b;table1;table2]
q)table1
a b d
1 4 7
1 5 8
3 4 9
1 4 6
q)table2
a b c
1 4 7
2 5 8
3 6 9
q)show aj[a
b;table1;table2]
a b d c
1 4 7 7
1 5 8 7
3 4 9
1 4 6 7
WHY NOT??
q)show aj[a
b;table1;table2]
a b d c
1 4 7 7
1 5 8
3 4 9
1 4 6 7
according to ?1 5? in table1, there is not matching records in table2.
Attila
2
Yes, it is doing the asof lookup on the b column
If you want a left join
q)table1 lj 2!table2
a b d c
1 4 7 7
1 5 8
3 4 9
1 4 6 7
Cheers,
Attila
Attila
James11
3
Attila,
q) show aj[a
b;table1;table2]
which means lookup on a column and b column ?
Attila
4
exact lookup on column a
asof (on or before) lookup on column b
http://code.kx.com/wiki/Reference/aj
Cheers,
Attila
Attila
Have a try:
show table2 asof a
b!(1;5) , you’ll got it.
Here, column b is correspond to a time column.