Accessing the last element of List of List

Community Support
1

x:(`Col1;12;.z.Z) y:(x;x;x) //add gtime of last element to end of x x,@[gtime;last x;0Np] //How do i do this for y?

So i think i did x correctly unless theres a better way. But how would i handle y? I want to append to end of each list in y. 

2

Hey @ekallivrousis - is this what you’re trying to do?

q)x:(`Col1;12;.z.Z)
q)y:(x;x;x)

Col1 12 2021.12.08T17:33:36.400 Col1 12 2021.12.08T17:33:36.400
`Col1 12 2021.12.08T17:33:36.400
q)y,'gtime .z.P

Col1 12 2021.12.08T17:33:36.400 2021.12.08D17:33:47.617397000 Col1 12 2021.12.08T17:33:36.400 2021.12.08D17:33:47.617397000
`Col1 12 2021.12.08T17:33:36.400 2021.12.08D17:33:47.617397000

 

Or are you looking to use the last item of each list of y (list of lists) as an input to gtime ?

3

Close, i want it to be in protected eval @, also i dont want to convert current .z.P i want to convert the last col of each list in y. I bold the column below that i want to use 

Col1 12 **2021.12.08T17:33:36.400** Col1 12 2021.12.08T17:33:36.400
`Col1 12 2021.12.08T17:33:36.400

4

This might be what you’re looking for then 

q) x1:(Col1;12;.z.Z) q) x2:(Col1;12;ERROR) q) show y:(x1;x1;x1;x2) Col1 12 2021.12.08T17:46:26.162 Col1 12 2021.12.08T17:46:26.162 Col1 12 2021.12.08T17:46:26.162 Col1 12 ERROR q) {x,@[gtime;last x;0Np]}each y Col1 12 2021.12.08T17:46:26.162 2021.12.08T17:46:26.162 Col1 12 2021.12.08T17:46:26.162 2021.12.08T17:46:26.162 Col1 12 2021.12.08T17:46:26.162 2021.12.08T17:46:26.162 Col1 12 `ERROR 0Np