Amend call, to pass list.

Community Support
1

Why does this fail ?
q)g:10#();

q)@[g;1 3 5;:;(1 2)#(100;100)]

'length

  [0]  @[g;1 3 5;:;(1 2)#(100;100)]

And how does this succeed?

q)@[g;1 3 5;:;3#(1 2)#(100;100)]

()

100 100

()

100 100

()

100 100

()

()

()

()

Thanks, 

Kumar

2

Hi,

It’s failing because the shape of (1 2)#(100;100) does not conform with the shape of your specified indices 1,3,5

The second example works because the operand has a count of 3 as does your list of indices.

Only when the operand is an atom is it extended to match the list of indices.. 

e.g. 

q)@[g;1 2 3;:;100]

()

100

100

100

()

()

()

()

()

()

whereas the following will fail 

q)@[g;1 2 3;:;enlist 100]

'length

  [0]  @[g;1 2 3;:;enlist 100]

       ^

Regards,

Jason

3

Ok, I was missing the part about atom operands and extension. Thanks, Jason. 
Kumar