Isaac
1
Hi,
Can I use knk function like below:
int number = 5;
K val = knk(number);
for(int i=0;i<number;i++)
{
switch(type)
{
case myInt:
kI(val)[i] = …;
…
}
}
k(handle, “insert”, ks(S(“tableName”)), val, (K)0);
If I can’t use it like this. how can I do the same thing?
effbiae
2
you want ktn - returns a k list from a type and count.
as you have a mixed list, t should be 0:
you’ll need to create k values depending on type
- case myInt: create a k int: ki(..)
(or maybe a kj() depending on your int size)
int number = 5;
K val = ktn(0,number); // instead of = knk(number);
for(int i=0;i<number;i++)
{
switch(type)
{
case myInt:
kK(val)[i]=ki(…); //instead of kI(val)[i] = …;
…
}
}
k(handle, “insert”, ks(S(“tableName”)), val, (K)0);
ta, jack (untested code above)