Hi Team,
I’m wondering how to use the @ (apply) paradigm to set a table column so that it accepts lists rather than atoms.
The below illustrates my problem. I can use @ (apply) to cast a column to an atomic data type but can’t seem to manage to get it to a listed datatype.
// define an empy table tbl:flip ref
stampnote
usr!(symbol$();
timestamp$();“”;()) //use apply to make column usr a symbol type: @[tbl;usr;{y$x};"s"] // works (test using meta tbl) //use apply to make column note a string type (nested character): @[tbl;
usr;{y$x};“C”] // does not work - result is a column of type c (single character) (test using meta tbl)
My question is:
Is there a way to use apply (@) to set a column in a table to a nested data type (so “C” for a string or “S” for a list of symbols for each record)?
Regards,
Simon
meta
on an empty table will never show C
. This is because kdb+ does not have a dedicated datatype for lists of lists. The empty list will be ()
which is of type 0h
. On a populated table meta inspects the first item in a list of lists and uses it’s type to populate it’s result. It cannot do this on an empty table.
q)tb:( a:1 2;b:(“wo”;“rd”)) q)tb a b ------ 1 “wo” 2 “rd” q)meta tb c| t f a -| ----- a| j b| C q)delete from tb
tb q)tb a b — q)meta tb c| t f a -| ----- a| j b| q).Q.s1 tb “+a
b!(`long$();())”
Thanks rocuinneagain - that’s good insight.
Given the above constraint, I have the following issue:
// define a table with the intention of loading a string to a columnn. // as discussed, it is empty so ‘uptar’ is defined as having type “c”. test: (test: $(); uptar:"C"$()); // With this done, I can't see a valid upsert to get a string into the uptar column. test upsert ([]test:
rta; uptar: enlist “ra”); test upsert (test: enlist rta; uptar: "ra"); test upsert ([]test: enlist
rta; uptar:enlist enlist “ra”); // finally, this one projects - so works but still not correctly. test upsert (test: `rta; uptar: “ra”);
Is it possible to insert a nested list into an empty table or must we use a ‘set’ workaround?
Thanks and regards,
Simon
Hi Simon,
You can leave the type of the (future) string column as empty in the table definition and let q infer the type once the first upsert occurs:
q)test: (test: $(); uptar:()); q)test upsert ([]test:
rta; uptar: enlist “ra”) test uptar ---------- rta “ra” q)meta test upsert (test: `rta; uptar: enlist “ra”) c | t f a -----| ----- test | s uptar| C
Happy Christmas!
I AM NOT WORTHY!!!
Great to hear from you David!
Thanks to you and rocuinneagain.
I appreciate both of you taking the time.
Both of you have a eGuinness on me.
(eDrinks: like real ones but rubbish)
Simon