flabby
1
Hi,
I am accessing kdb+ from R and when I access data, the time is in integers. Can anyone help me convert it to standard sate time? I tired setting system time: http://code.kx.com/wiki/Cookbook/IntegratingWithR#Connecting\_from\_R\_to\_kdb.2B\_.28a.k.a.\_Q\_Server\_for\_R.29 as given here but it didn’t work.
Thanks!
This is normal because kdb time is mapped to integers in r.<o:p></o:p>
<o:p> </o:p>
What you can do is to add date to time to get a timestamp.<o:p></o:p>
<o:p> </o:p>
r-code:<o:p></o:p>
<o:p> </o:p>
kdb<-open_connection(,8888)<o:p></o:p>
<o:p> </o:p>
execute(kdb,.z.t)<o:p></o:p>
[1] 77657658 <o:p></o:p>
<o:p> </o:p>
execute(kdb,.z.d + .z.t)<o:p></o:p>
[1] “2015-12-01 21:34:17 GMT”<o:p></o:p>
<o:p> </o:p>
Kim<o:p></o:p>
<o:p> </o:p>
Von: personal-kdbplus@googlegroups.com [mailto:personal-kdbplus@googlegroups.com] Im Auftrag von flabby
Gesendet: Dienstag, 1. Dezember 2015 04:30
An: Kdb+ Personal Developers
Betreff: [personal kdb+] kdb+ and R<o:p></o:p>
<o:p> </o:p>
Hi,<o:p></o:p>
<o:p> </o:p>
I am accessing kdb+ from R and when I access data, the time is in integers. Can anyone help me convert it to standard sate time? I tired setting system time: http://code.kx.com/wiki/Cookbook/IntegratingWithR#Connecting_from_R_to_kdb.2B_.28a.k.a._Q_Server_for_R.29 as given here but it didn’t work.<o:p></o:p>
<o:p> </o:p>
Thanks!<o:p></o:p>
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Submitted via Google Groups