Tickerplant subscription by sym

Community Support
1

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down vote[favorite](“http://stackoverflow.com/questions/38832447/tickperplant-subscription-by-sym#” "“Click”)

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I have a ticker plant that has the schema:

quote:([]time:(); sym:();expiration:();mtype:();price:();cond:();exchange:();volume:())trade:([]time:(); sym:();expiration:();mtype:();price:();cond:();exchange:();volume:())rfills:([]time:();sym:();expiration:();tag:();price:();volume:())

I then double check the schema by doing

meta trade

"table

I subscribe to the tickerplant as such getting the trade table

h(`.u.sub;`trade;`)

But when I try to specify a symbol from sym by doing

h(`.u.sub;`trade;`ZB)

No records are being pushed, This is odd because when I subscribe to all syms you can see that `ZB is definitely sym being pushed as shown below after setting upd to show "enter

Any idea why its not working when I specify the sym

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2

You can check .u.w at ticker plant.<o:p></o:p>

make sure `ZB is in the dictionary.<o:p></o:p>

<o:p> </o:p>

???: personal-kdbplus@googlegroups.com [mailto:personal-kdbplus@googlegroups.com] ?? rtrader
???: 2016?8?8? 23:53
???: Kdb+ Personal Developers <personal-kdbplus@googlegroups.com>
??: [personal kdb+] Tickerplant subscription by sym<o:p></o:p>

<o:p> </o:p>

<o:p> </o:p>

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down vote[favorite](“http://stackoverflow.com/questions/38832447/tickperplant-subscription-by-sym” "“Click”)<o:p></o:p>

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I have a ticker plant that has the schema:<o:p></o:p>

quote:([]time:(); sym:();expiration:();mtype:();price:();cond:();exchange:();volume:())

trade:([]time:(); sym:();expiration:();mtype:();price:();cond:();exchange:();volume:())

rfills:([]time:();sym:();expiration:();tag:();price:();volume:())

I then double check the schema by doing<o:p></o:p>

meta trade

"table<o:p></o:p>

I subscribe to the tickerplant as such getting the trade table<o:p></o:p>

h(`.u.sub;`trade;`)

But when I try to specify a symbol from sym by doing<o:p></o:p>

h(`.u.sub;`trade;`ZB)

No records are being pushed, This is odd because when I subscribe to all syms you can see that `ZB is definitely sym being pushed as shown below after setting upd to show "enter<o:p></o:p>

Any idea why its not working when I specify the sym<o:p></o:p>

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Submitted via Google Groups

3

This is what is confusing when I evaluated .u.w I got 
But when I evaluated it again I got 
On Monday, August 8, 2016 at 9:24:51 PM UTC-5, Roy wrote:

You can check .u.w at ticker plant.

make sure `ZB is in the dictionary.

 

???: personal…@googlegroups.com [mailto:personal…@googlegroups.com] ?? rtrader
???: 2016?8?8? 23:53
???: Kdb+ Personal Developers <personal…@googlegroups.com>
??: [personal kdb+] Tickerplant subscription by sym

 

 

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down vote[favorite](“http://stackoverflow.com/questions/38832447/tickperplant-subscription-by-sym” "“Click”)

|

I have a ticker plant that has the schema:

quote:(time:(); sym:();expiration:();mtype:();price:();cond:();exchange:();volume:())

trade:(time:(); sym:();expiration:();mtype:();price:();cond:();exchange:();volume:())

rfills:(time:();sym:();expiration:();tag:();price:();volume:())

I then double check the schema by doing

meta trade

"table

I subscribe to the tickerplant as such getting the trade table

h(.u.sub;trade;`)

But when I try to specify a symbol from sym by doing

h(.u.sub;trade;`ZB)

No records are being pushed, This is odd because when I subscribe to all syms you can see that `ZB is definitely sym being pushed as shown below after setting upd to show "enter

Any idea why its not working when I specify the sym

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Submitted via Google Groups

4

Send this from your subscriber and let us know what it returns:

h"(.u.w;.z.w)"

5

it returns:
(logmsgquoterfillstradetradee!(((472i;);(480i;);(476i;));((472i;);(480i;);(476i;));((472i;);(480i;);(476i;));((472i;);(480i;);(476i;);(500i;));((472i;);(480i;);(476i;`)));500i)

6

That’s the subscription to all though right, that’s the one that works.

What does it turn for your subscriber to `ZB only?

7

sorry about that when I subscribe to `ZB only I get

(logmsgquoterfillstradetradee!(((472i;);(480i;);(476i;));((472i;);(480i;);(476i;));((472i;);(480i;);(476i;));((472i;);(480i;);(476i;);(488i;ZB));((472i;);(480i;);(476i;`)));488i)

8

I can’t see how you’re not getting it then!

Might be an idea to (temporarily) capture all incoming messages to your subscriber… Assuming it’s a kdb process that’s subscribing. Define the following:

incoming:();
.z.ps:{incoming,:enlist x;value x}

Then inspect the incoming to see if it’s something in your subscriber.

If your incoming remains empty, then either there are no `ZB messages being sent, or the TP is hitting an error as it tries to publish to you.

9

Must be something with the tickerplant I guess, will keep investigating. Extremely frustrating as I cant pin point whats wrong here. incoming is empty when subscribing to `ZB but populates when subscribing to all syms

10

Figured out what washappening here. So I was publishing a single record not a table from qSharp:

string giantstring2 = ".u.upd[" + "trade;" + qdatetime + “,” + rsymbol + “,” + rexp + “,” + qtype + “,” + qprice + “,” + qcondition + “,” + qexchange + “,” + qvolume + " ]"; q.Async(giantstring2);`

I then set .u.upd to be .u.pub . So clients are recieve the single record but since its not a table nor a key value pair it doesn’t grab the sym. So then I decided to change .u.upd to be 

So now subscribing by sym works however there is another issue, now it keeps publishes the entire table not just the record. Thinking of how to make this do what I want however I’m not sure how to go about it. Upon investigation of the .u.pub function 

{[t;x]{[t;x;w]if[count x:sel[x]w 1;(neg first w)(upd;t;x)]}[t;x]each w t}`

It looks like it goes through the table and publishes each record. I assume I can edit this to just submit the last record and everything should work how I expect it to. Although I am unsure how to that. Any ideas?