hi guys,
why won’t d behave as a dyad in scan:
d:“ab”!((0 1!“ab”);(0 1!“ba”))
"a"d\0 1 0 1 1
'type
when:
“a”{d[x;y]}\0 1 0 1 1
“abbab”
“a”{d .(x;y)}\0 1 0 1 1
“abbab”
i’m guessing a dictionary is considered a monad - regardless of whether it returns another dictionary. is a mixed list considered a dyad as in:
s (0 1;1 0)\x
regards,
jack.
I think your guess is quite correct.
f[y] and f[x;y] are not always equivalent, as the former works for both monad+monad and dyad, while the latter works only for dyad.
> f[y] and f[x;y] are not always equivalent, .. while the latter works only for dyad.
q)d:“ab”!((0 1!“ab”);(0 1!“ba”))
q)d[“a”;0]
“a”
even so, dictionaries appear to be considered monad?