May I please ask why creating a table from a table results in a “list” of dictionaries?
( tab) where tab is a table(98h) results in a list of dictionaries?
Thank you!
May I please ask why creating a table from a table results in a “list” of dictionaries?
( tab) where tab is a table(98h) results in a list of dictionaries?
Thank you!
First, remember that a table itself is just a list of dictionaries.
q)0N!/:tab; col1
col2!(a;1)
col1col2!(
b;2) col1
col2!(`c;3)
So, when you tabulate a table, each entry in the original table (a dictionary) just becomes an entry in the new table column:
q)(tab) tab ----------------- col1
col2!(a;1)
col1col2!(
b;2) col1
col2!(`c;3) q)type (tab) 98h q)type each tab 99 99 99h q)type each(tab) 99 99 99h
A non-keyed table is just a list of dictionaries, flipped:
q)tab:(a:1 2 3;b:a
bc) tab a b --- 1 a 2 b 3 c q)
ab!(1 2 3;
ab
c) a| 1 2 3 b| a b c q)flip a
b!(1 2 3;a
bc) a b --- 1 a 2 b 3 c q)tab~flip
ab!(1 2 3;
ab
c) 1b
What you are doing here is creating a new table, with a column called tab. This new column has a record for each row of the original table as a dictionary
q)tab:(a:1 2 3;b:a
bc) tab a b --- 1 a 2 b 3 c q)([]tab) tab -----------
ab!(1;
a) a
b!(2;b)
ab!(3;
c)
You can also enlist the table to create a single record in the new table:
q)( enlist tab) tab -------------------- +a
b!(1 2 3;a
b`c)
If you want to create a table from a table, typically you would utilise query filtering to select a subset of columns, or joins from another table. What is your use case here?